9h^2+2h-1224=0

Solution for 9h^2+2h-1224=0 equation:

9h^2+2h-1224=0

a = 9; b = 2; c = -1224;
Δ = b2-4ac
Δ = 22-4·9·(-1224)
Δ = 44068
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{44068}=\sqrt{4*11017}=\sqrt{4}*\sqrt{11017}=2\sqrt{11017}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{11017}}{2*9}=\frac{-2-2\sqrt{11017}}{18}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{11017}}{2*9}=\frac{-2+2\sqrt{11017}}{18}
$